## College Algebra (10th Edition)

$x=0$ or $x=\frac{1}{3}$
We solve: $3x^{2}-x=0$ First we factor out $x$: $x(3x-1)=0$ Next we set each term equal to $0$ and solve for $x$: $x=0$ or $3x-1=0$ $x=0$ or $3x=1$ $x=0$ or $x=\frac{1}{3}$