College Algebra (10th Edition)

Published by Pearson
ISBN 10: 0321979478
ISBN 13: 978-0-32197-947-6

Chapter 3 - Cumulative Review - Page 271: 4


$x=\frac{1}{3}$ or $x=\frac{1}{2}$

Work Step by Step

We solve: $6x^{2}-5x+1=0$ We factor using the formula $(a+b)(c+d)=ac+ad+bc+bd$: $(3x-1)(2x-1)=0$ $3x-1=0$ or $2x-1=0$ $3x=1$ or $2x=1$ $x=\frac{1}{3}$ or $x=\frac{1}{2}$
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