## College Algebra (10th Edition)

$x=\frac{1}{3}$ or $x=\frac{1}{2}$
We solve: $6x^{2}-5x+1=0$ We factor using the formula $(a+b)(c+d)=ac+ad+bc+bd$: $(3x-1)(2x-1)=0$ $3x-1=0$ or $2x-1=0$ $3x=1$ or $2x=1$ $x=\frac{1}{3}$ or $x=\frac{1}{2}$