College Algebra (10th Edition)

Published by Pearson
ISBN 10: 0321979478
ISBN 13: 978-0-32197-947-6

Chapter 2 - Section 2.5 - Variation - 2.5 Assess Your Understanding - Page 192: 25


See below.

Work Step by Step

$s=kt^2$, hence here $16=k\cdot1^2$, thus $k=16$ Thus after $t=3s$, $s=16\cdot3^2=144$ Hence $64=16t^2$, so $t=\pm2$, the negative value doesn't make sense, thus it takes $2$ seconds.
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