College Algebra (10th Edition)

Published by Pearson
ISBN 10: 0321979478
ISBN 13: 978-0-32197-947-6

Chapter 2 - Section 2.5 - Variation - 2.5 Assess Your Understanding - Page 192: 22

Answer

$T=2\pi\sqrt{\dfrac{l}{32}}$

Work Step by Step

$y$ varies $\bf{directly}$ with $x,$ or $y$ is directly proportional to $x$, if there is a nonzero number $k$ such that$ \ \ y=kx.$ The number $k$ is called the constant of proportionality. --- Here, $T=k\sqrt{l},$ Given that $k=\displaystyle \frac{2\pi}{\sqrt{32}}$, this becomes $T=\displaystyle \frac{2\pi}{\sqrt{32}}\cdot\sqrt{l}.$ or $T=2\pi\sqrt{\dfrac{l}{32}}$
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