College Algebra (10th Edition)

Published by Pearson
ISBN 10: 0321979478
ISBN 13: 978-0-32197-947-6

Chapter 2 - Section 2.5 - Variation - 2.5 Assess Your Understanding - Page 192: 23

Answer

$941.05$

Work Step by Step

$p=kB$, hence here $6.49=k\cdot1000$, thus $k=0.00649$ Hence if $B=145000$, then $p=0.00649\cdot145000=941.05$
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