Answer
slope: $-\displaystyle \frac{3}{2}$, y-intercept: $0$.
Work Step by Step
If possible, write in the form $\quad y=mx+b$
$3x+2y=0$
$2y= -3x\qquad/\div 2$
$y=-\displaystyle \frac{3}{2}x$
slope: $-\displaystyle \frac{3}{2}$, y-intercept: $0$.
Graphing when we know m and b:
Write m as a fraction, positive denominator, $m=\displaystyle \frac{\pm u}{v}.$
Start from $(0,b)$. Move v units to the right, and u units up or down, depending on the sign.
In this way you arrive at a second point, which is enough to define a line.
$m=\displaystyle \frac{-3}{2}$
$(0,0)\rightarrow(0+2,0-3)=(2,-3)$