College Algebra (10th Edition)

Published by Pearson
ISBN 10: 0321979478
ISBN 13: 978-0-32197-947-6

Chapter 2 - Section 2.3 - Lines - 2.3 Assess Your Understanding - Page 179: 62



Work Step by Step

RECALL: (1) The slope-intercept form of a line's equation is: $y=mx+b$ where $m$ = slope and $b$ = y-intercept (2) Parallel lines have the same (equal) slopes. (3) Perpendicular lines have slopes whose product is $-1$ (negative reciprocals of each other). The line is parallel to the line $y=-3x$ (whose slope is $-3$). This means that the line we are looking for also has a slope of $-3$. Thus, the tentative equation of the line is: $y=-3x+b$ To find the value of $b$, substitute the x and y values of the given point to the tentative equation above to obtain: $y=-3x+b \\2=-3(-1)+b \\2 = 3+b \\2-3=b \\-1=b$ Therefore, the equation of the line is: $\color{blue}{y=-3x-1}$
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