Answer
$\color{blue}{y=\dfrac{1}{2}x-\dfrac{1}{2}}$
Work Step by Step
RECALL:
The slope-intercept form of a line's equation is:
$y=mx+b$
where $m$=slope and $b$ = y-intercept.
The line has a slope of $\dfrac{1}{2}$ so the tentative equation of the line is:
$y=\dfrac{1}{2}x+b$
To find the value of $b$, substitute the x and y values given in the problem into the tentative equation above to obtain:
$y=\dfrac{1}{2}x+b
\\1=\dfrac{1}{2}(3)+b
\\1=\dfrac{3}{2}+b
\\1-\dfrac{3}{2}=b
\\\dfrac{2}{2}-\dfrac{3}{2}=b
\\-\dfrac{1}{2}=b$
Therefore, the equation of the line is $\color{bluehe }{y=\dfrac{1}{2}x-\dfrac{1}{2}}$.