## College Algebra (10th Edition)

Published by Pearson

# Chapter 2 - Section 2.3 - Lines - 2.3 Assess Your Understanding - Page 179: 50

#### Answer

$\color{blue}{y=\dfrac{1}{2}x-\dfrac{1}{2}}$

#### Work Step by Step

RECALL: The slope-intercept form of a line's equation is: $y=mx+b$ where $m$=slope and $b$ = y-intercept. The line has a slope of $\dfrac{1}{2}$ so the tentative equation of the line is: $y=\dfrac{1}{2}x+b$ To find the value of $b$, substitute the x and y values given in the problem into the tentative equation above to obtain: $y=\dfrac{1}{2}x+b \\1=\dfrac{1}{2}(3)+b \\1=\dfrac{3}{2}+b \\1-\dfrac{3}{2}=b \\\dfrac{2}{2}-\dfrac{3}{2}=b \\-\dfrac{1}{2}=b$ Therefore, the equation of the line is $\color{bluehe }{y=\dfrac{1}{2}x-\dfrac{1}{2}}$.

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