College Algebra (10th Edition)

Published by Pearson
ISBN 10: 0321979478
ISBN 13: 978-0-32197-947-6

Chapter 2 - Section 2.3 - Lines - 2.3 Assess Your Understanding - Page 178: 27

Answer

point-slope form: $y-4=-\dfrac{3}{4}(x-2)$ Refer to the image below for the graph.

Work Step by Step

(A) To graph the line with the given point and slope (slope is $\dfrac{\text{rise}}{\text{run}}$), perform the following steps: (1) Plot the point P(2, 4). (2) Use the slope $-\dfrac{3}{4}$ to get another point on the line. From $(2, 4)$, move 3 units downward (the rise) and 4 units to the right (the run) to arrive at the point $(6, 1)$. (3) Connect the two points using a straight line to complete the graph. (refer to the attached image below) (B) The point slope form of a line's equation is $y-y_1 = m(x-x_1)$ where $m$= slope and $(x_1, y_1)$ is a point on the line. With $m=-\dfrac{3}{4}$ and $P(2, 4)$ on the line, the point-slope form of the equation of the line is: $y-4=-\dfrac{3}{4}(x-2)$
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