## College Algebra (10th Edition)

$3;\\ 2$
RECALL: (1) The y-intercept can be found by setting $x=0$ then solving for $y$. (2) The x-intercept can be found by setting $y=0$ and solving for $x$. Solving for the intercepts gives: x-intercept: $2x+3y=6 \\2x+3(0) = 6 \\2x=6 \\x=\frac{6}{2} \\x=3$ y-intercept: $2x+3y=6 \\2(0)+3y = 6 \\3y=6 \\y = \frac{6}{2} \\y=2$ Thus, the missing expressions in the given statements are (in order): 3; 2