College Algebra (10th Edition)

Published by Pearson
ISBN 10: 0321979478
ISBN 13: 978-0-32197-947-6

Chapter 10 - Review Exercises - Page 708: 18

Answer

See below.

Work Step by Step

According to the Multiplication Principle, if we have $p$ selections for the first choice, $q$ selections for the second choice, then we have $p\cdot q$ different ways of selections and so on for more choices... Here we have $26-2=24$ possibilities for the first character, $10-1=9$ options for the first number and $10$ possibilities for the other three numbers, thus the number of possibilities is $24\cdot9\cdot10^3=216000$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.