College Algebra (10th Edition)

Published by Pearson
ISBN 10: 0321979478
ISBN 13: 978-0-32197-947-6

Chapter 10 - Review Exercises - Page 708: 16

Answer

91

Work Step by Step

This is a combination problem since we do not care which team is at home. $n_{C_r}=\frac{n!}{(n-r)!r!}$ $=\frac{14!}{(14-2)!*2!}=14*13/2=91$
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