Answer
{0}, {Dave},{Joanne},{Erica}, {Joanne, Erica},{Joanne, Dave},{Dave, Erica}, {Joanne, Erica, Dave}
Work Step by Step
The number of subsets we have is $2^n$ where $n$ is the number of elements.
We have the null set, {0},
We have the single groupings, {Dave},{Joanne},{Erica}
The doubles, {Joanne, Erica},{Joanne, Dave},{Dave, Erica}
And the triple {Joanne, Erica, Dave}