College Algebra (10th Edition)

Published by Pearson
ISBN 10: 0321979478
ISBN 13: 978-0-32197-947-6

Chapter 1 - Section 1.7 - Problem Solving: Interest, Mixture, Uniform Motion, Constant Rate Job Applications - 1.7 Asses Your Understanding - Page 141: 27


$2.285$ miles an hour.

Work Step by Step

Let $x$ be the current velocity, then the upstream velocity is $16-x$, the downstream velocity is $16+x$. Then our equation is: $(16-x)\cdot20=(16+x)\cdot15\\320-20x=240+15x\\80=35x\\x\approx2.285$ Thus the current speed is $2.285$ miles an hour.
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.