College Algebra (10th Edition)

Published by Pearson
ISBN 10: 0321979478
ISBN 13: 978-0-32197-947-6

Chapter 1 - Section 1.7 - Problem Solving: Interest, Mixture, Uniform Motion, Constant Rate Job Applications - 1.7 Asses Your Understanding - Page 141: 16

Answer

$K=\frac{1}{2}mv^2$

Work Step by Step

We translate the sentence into an equation: $Kinetic\ energy=\frac{1}{2}*mass*velocity^2$ $K=\frac{1}{2}mv^2$
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