College Algebra (10th Edition)

Published by Pearson
ISBN 10: 0321979478
ISBN 13: 978-0-32197-947-6

Chapter 1 - Section 1.1 - Linear Equations - 1.1 Assess Your Understanding - Page 91: 87

Answer

Score needed = 85

Work Step by Step

Average = Sum of items $\div$ Number of items Required average = 80 As the last test counts as 2 exams, let the score be "2x"; one "x" per test score. = $ \frac{80 + 83 + 71 + 61 + 95 + x + x}{7} = 80$ = 390 + 2x = 560 2x = 560 - 390 2x = 170 x = 85 Score needed = 85
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