College Algebra (10th Edition)

Published by Pearson
ISBN 10: 0321979478
ISBN 13: 978-0-32197-947-6

Chapter 1 - Section 1.1 - Linear Equations - 1.1 Assess Your Understanding - Page 91: 71



Work Step by Step

$ax-b=c$ for $a\ne0$ First, we take b to the right side by adding it to both sides. $ax-b+b=c+b$ $ax=c+b$ Now, to solve for x, we get rid of its constant, a, by dividing it to all the terms. $\frac{ax}{a}=\frac{c+b}{a}$ $x=\frac{c+b}{a}$
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