## College Algebra (10th Edition)

$x=\frac{c+b}{a}$
$ax-b=c$ for $a\ne0$ First, we take b to the right side by adding it to both sides. $ax-b+b=c+b$ $ax=c+b$ Now, to solve for x, we get rid of its constant, a, by dividing it to all the terms. $\frac{ax}{a}=\frac{c+b}{a}$ $x=\frac{c+b}{a}$