## College Algebra (10th Edition)

$x=\frac{b-1}{-a}$
$1-ax=b$ for $a\ne0$ First, we subtract both sides by 1. $1-1-ax=b-1$ $-ax=b-1$ Now, we divide both sides by -a. $\frac{-ax}{-a}=\frac{b-1}{-a}$ $x=\frac{b-1}{-a}$