#### Answer

The solution is $(-1,2)$.

#### Work Step by Step

The given system is
$y=-2x^2-4x$ ...... (1)
$y=2$ ...... (2)
Graph each equation.
The point of intersection is $A=(-1,2)$.
Check: $(x,y)=(-1,2)$
Equation (1).
$\Rightarrow y=-2x^2-4x$
$\Rightarrow 2=-2(-1)^2-4(-1)$
$\Rightarrow 2=-2+4$
$\Rightarrow 2=2$
True.
Equation (2).
$\Rightarrow y=2$
$\Rightarrow 2=2$
True.
Hence, the solution is $(-1,2)$.