## Algebra and Trigonometry 10th Edition

(a) $\frac{1}{2}$ (b) It is not possible because we can not perform a division in which the denominator is equal to 0.
$\frac{x}{x-3}$ (a) $x=-3$ $\frac{-3}{-3-3}=\frac{-3}{-6}=\frac{1}{2}$ (b) $x=3$ $\frac{3}{3-3}=\frac{3}{0}$. It is not possible.