Algebra and Trigonometry 10th Edition

Published by Cengage Learning
ISBN 10: 9781337271172
ISBN 13: 978-1-33727-117-2

Prerequisites - Review Exercises - Page 62: 34


(a) $(x+2)^6$ (b) $\frac{8(b-3)^3}{15}$

Work Step by Step

(a) $[(x+2)^2]^3=(x+2)^{2\times3}=(x+2)^6$ (b) $\frac{40(b-3)^5}{75(b-3)^2}=\frac{5(8)(b-3)^2(b-3)^3}{5(15)(b-3)^2}=\frac{8(b-3)^3}{15}$
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