Answer
(a) $(x+2)^6$
(b) $\frac{8(b-3)^3}{15}$
Work Step by Step
(a) $[(x+2)^2]^3=(x+2)^{2\times3}=(x+2)^6$
(b) $\frac{40(b-3)^5}{75(b-3)^2}=\frac{5(8)(b-3)^2(b-3)^3}{5(15)(b-3)^2}=\frac{8(b-3)^3}{15}$
Algebra and Trigonometry 10th Edition
by Larson, Ron
Published by
Cengage Learning
ISBN 10:
9781337271172
ISBN 13:
978-1-33727-117-2
Prerequisites - Review Exercises - Page 62: 34
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