Algebra and Trigonometry 10th Edition

Published by Cengage Learning
ISBN 10: 9781337271172
ISBN 13: 978-1-33727-117-2

Prerequisites - P.6 - The Rectangular Coordinate System and Graphs - Exercises - Page 57: 21

Answer

$\approx 2.77$ units

Work Step by Step

We are given the points: $\left(\dfrac{1}{2},\dfrac{4}{3}\right)$ $(2,-1)$ Determine the distance between two points $(x_1,y_1),(x_2,y_2)$ using the formula: $d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$ $d=\sqrt{\left(2-\dfrac{1}{2}\right)^2+\left(-1-\dfrac{4}{3}\right)^2}$ $=\sqrt{\dfrac{9}{4}+\dfrac{49}{9}}$ $=\sqrt{\dfrac{277}{36}}$ $=\dfrac{\sqrt{277}}{6}$ $\approx 2.77$
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