Algebra and Trigonometry 10th Edition

Published by Cengage Learning
ISBN 10: 9781337271172
ISBN 13: 978-1-33727-117-2

Prerequisites - P.6 - The Rectangular Coordinate System and Graphs - Exercises - Page 57: 17

Answer

13

Work Step by Step

$(x_{1},y_{1}) = (-2,6)$ and $(x_{2},y_{2}) = (3,-6)$ Then apply the distance formula ,ie, $d = \sqrt {(x_{1}-y_{1})^{2}+(x_{2}-y_{2})^{2}}$ $d = \sqrt {(-2-3)^{2}+(6-(-6))^{2}}$ $d = \sqrt {(-5)^{2}+(12)^{2}}$ $d = \sqrt {25+144} = \sqrt {169} = 13$
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