Answer
$(3+4)^2=49\ne25=3^3+4^2$
$(x+y)^2=x^2+y^2$ if $x=0$ or $y=0$
Work Step by Step
$(3+4)^2=7^2=49$
$3^3+4^2=9+16=25$
$(x+y)^2=x^2+y^2$
$x^2+2xy+y^2=x^2+y^2$
$2xy=0$
$xy=0$
$x=0$ or $y=0$
Algebra and Trigonometry 10th Edition
by Larson, Ron
Published by
Cengage Learning
ISBN 10:
9781337271172
ISBN 13:
978-1-33727-117-2
Prerequisites - P.3 - Polynomials and Special Products - Exercises - Page 33: 92
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