Answer
$(x-3)^2=x^2-6x+9$
Work Step by Step
The second term of the square of a binomial is missing.
$(a-b)^2=a^2-2ab+b^2$
So:
$(x-3)^2=x^2-2(x)(3)+3^2=x^2-6x+9$
Algebra and Trigonometry 10th Edition
by Larson, Ron
Published by
Cengage Learning
ISBN 10:
9781337271172
ISBN 13:
978-1-33727-117-2
Prerequisites - P.3 - Polynomials and Special Products - Exercises - Page 33: 89
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