Algebra and Trigonometry 10th Edition

Published by Cengage Learning
ISBN 10: 9781337271172
ISBN 13: 978-1-33727-117-2

Prerequisites - P.3 - Polynomials and Special Products - Exercises - Page 32: 76



Work Step by Step

Let A be the area of the bigger triangle. Hence, A = $\frac{1}{2}(9x)(12x)=54x^2$ Let B be the area of the smaller triangle. Hence, B = $\frac{1}{2}(6x)(8x)=24x^2$ Subtract B from A. Answer = A - B = $54x^2 - 24x^2 = 30x^2$
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