## Algebra and Trigonometry 10th Edition

$3x^2+8x$
Let A be the area of the larger rectangle. Hence, A = 2x(2x+6)=$4x^2+12x$ Let B be the area of the smaller rectangle. Hence, B = x(x+4) = $x^2+4x$ Subtract B from A. ans = A - B = $4x^2+12x$ - $x^2-4x$ = $3x^2+8x$