## Algebra and Trigonometry 10th Edition

$d=\sqrt {10}$
$a+bi=3+2i$ and $s+ti=2-i$ $d=\sqrt {(s-a)^2+(t-b)^2}=\sqrt {(2-3)^2+(-1-2)^2}=\sqrt {(-1)^2+(-3)^2}=\sqrt {1+9}=\sqrt {10}$