Algebra and Trigonometry 10th Edition

Published by Cengage Learning
ISBN 10: 9781337271172
ISBN 13: 978-1-33727-117-2

Chapter 8 - Review Exercises - Page 618: 107

Answer

$d=\sqrt {10}$

Work Step by Step

$a+bi=3+2i$ and $s+ti=2-i$ $d=\sqrt {(s-a)^2+(t-b)^2}=\sqrt {(2-3)^2+(-1-2)^2}=\sqrt {(-1)^2+(-3)^2}=\sqrt {1+9}=\sqrt {10}$
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