Answer
$\frac{tan~25°+tan~110°}{1-tan~25°~tan~110°}=-1$
Work Step by Step
$tan(u+v)=\frac{tan~u+tan~v}{1-tan~u~tan~v}$
$\frac{tan~25°+tan~110°}{1-tan~25°~tan~110°}=tan(25°+110°)=tan~135°=-1$
Algebra and Trigonometry 10th Edition
by Larson, Ron
Published by
Cengage Learning
ISBN 10:
9781337271172
ISBN 13:
978-1-33727-117-2
Chapter 7 - 7.4 - Sum and Difference Formulas - 7.4 Exercises - Page 538: 40
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