Algebra and Trigonometry 10th Edition

Published by Cengage Learning
ISBN 10: 9781337271172
ISBN 13: 978-1-33727-117-2

Chapter 7 - 7.4 - Sum and Difference Formulas - 7.4 Exercises - Page 538: 31



Work Step by Step

$tan(u+v)=\frac{tan~u+tan~v}{1-tan~u~tan~v}$ $\frac{tan~\frac{\pi}{15}+tan~\frac{2\pi}{5}}{1-tan~\frac{\pi}{15}~tan~\frac{2\pi}{5}}=tan(\frac{\pi}{15}+\frac{2\pi}{5})=tan(\frac{\pi}{15}+\frac{2\pi(3)}{5(3)})=tan(\frac{\pi}{15}+\frac{6\pi}{15})=tan(\frac{7\pi}{15})$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.