## Algebra and Trigonometry 10th Edition

$x=\frac{\pi}{4}$ and $x=\frac{5\pi}{4}$
$sin~x-2=cos~x-2$ $sin~x=cos~x-2+2$ $sin~x=cos~x$ $\frac{sin~x}{cos~x}=1$ $tan~x=1$ The solutions in the interval $[0,2\pi)$ are: $x=\frac{\pi}{4}$ and $x=\frac{5\pi}{4}$