## Algebra and Trigonometry 10th Edition

$x=\frac{2\pi}{3}+n\pi$
$tan~x+\sqrt 3=0$ $tan~x=-\sqrt 3$ The period of $tan~x$ is $\pi$. The solution in the interval: $[0,\pi)$ is: $x=\frac{2\pi}{3}$ Now, add multiples of $\pi$ to the solution: $x=\frac{2\pi}{3}+n\pi$