Answer
$x=\frac{2\pi}{3}+n\pi$
Work Step by Step
$tan~x+\sqrt 3=0$
$tan~x=-\sqrt 3$
The period of $tan~x$ is $\pi$. The solution in the interval: $[0,\pi)$ is:
$x=\frac{2\pi}{3}$
Now, add multiples of $\pi$ to the solution:
$x=\frac{2\pi}{3}+n\pi$
