Identity is verified. $tan^5x=tan^3~sec^2x-tan^3x$
Work Step by Step
We know that: $1+tan^2x=sec^2x$ $tan^2x=sec^2x-1$ Start at the right side of the equation: $tan^3~sec^2x-tan^3x=tan^3x(sec^2x-1)=tan^3x(tan^2x)=tan^5x$
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