Answer
Identity is verified.
$tan^5x=tan^3~sec^2x-tan^3x$
Work Step by Step
We know that:
$1+tan^2x=sec^2x$
$tan^2x=sec^2x-1$
Start at the right side of the equation:
$tan^3~sec^2x-tan^3x=tan^3x(sec^2x-1)=tan^3x(tan^2x)=tan^5x$
Algebra and Trigonometry 10th Edition
by Larson, Ron
Published by
Cengage Learning
ISBN 10:
9781337271172
ISBN 13:
978-1-33727-117-2
Chapter 7 - 7.2 - Verifying Trigonometric Identities - 7.2 Exercises - Page 521: 51
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