Algebra and Trigonometry 10th Edition

Published by Cengage Learning
ISBN 10: 9781337271172
ISBN 13: 978-1-33727-117-2

Chapter 6 - Chapter Test - Page 503: 9


$sin~\theta=-\frac{4}{5}$ $tan~\theta=-\frac{4}{3}$ $cot~\theta=-\frac{3}{4}$ $sec~\theta=\frac{5}{3}$ $csc~\theta=-\frac{5}{4}$

Work Step by Step

If $cos~\theta\gt0$ and $tan~\theta\lt0$, then $sin~\theta\lt0$ $cos^2\theta+sin^2\theta=1$ $\frac{9}{25}+sin^2\theta=1$ $sin^2\theta=\frac{16}{25}$ $sin~\theta=-\frac{4}{5}$ $tan~\theta=\frac{sin~\theta}{cos~\theta}=-\frac{4}{3}$ $cot~\theta=\frac{cos~\theta}{sin~\theta}=-\frac{3}{4}$ $sec~\theta=\frac{1}{cos~\theta}=\frac{5}{3}$ $csc~\theta=\frac{1}{sin~\theta}=-\frac{5}{4}$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.