Algebra and Trigonometry 10th Edition

Published by Cengage Learning
ISBN 10: 9781337271172
ISBN 13: 978-1-33727-117-2

Chapter 6 - Chapter Test - Page 503: 10

Answer

$tan~\theta=-\frac{21}{20}$ $cos~\theta=-\frac{20}{29}$ $sin~\theta=\frac{21}{29}$ $cot~\theta=-\frac{20}{21}$ $csc~\theta=\frac{29}{21}$

Work Step by Step

If $sec~\theta\lt0$ and $sin~\theta\gt0$, then $tan~\theta\lt0$ $sec^2\theta=1+tan^2\theta$ $tan^2\theta=(-\frac{29}{20})^2-1=\frac{441}{400}$ $tan~\theta=-\frac{21}{20}$ $cos~\theta=\frac{1}{sec~\theta}=-\frac{20}{29}$ $sin^2\theta=1-cos^2\theta=1-\frac{400}{841}=\frac{441}{841}$ $sin~\theta=\frac{21}{29}$ $cot~\theta=\frac{1}{tan~\theta}=-\frac{20}{21}$ $csc~\theta=\frac{1}{sin~\theta}=\frac{29}{21}$
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