Algebra and Trigonometry 10th Edition

Published by Cengage Learning
ISBN 10: 9781337271172
ISBN 13: 978-1-33727-117-2

Chapter 6 - 6.7 - Applications and Models - 6.7 Exercises - Page 494: 8

Answer

$A=8.4°$ $B=81.6°$ $C=90°$ $a=40.5$ $b=274.27$ $c=277.24$

Work Step by Step

$A=8.4°$, $C=90°$ (right triangle) $A+B+C=180°$ $8.4°+B+90°=180°$ $B=180°-90°-8.4°$ $B=81.6°$ $a=40.5$ $sin~A=\frac{opp}{hyp}=\frac{a}{c}=\frac{40.5}{c}$ $c=\frac{40.5}{sin~8.4°}=277.24$ $tan~A=\frac{opp}{adj}=\frac{a}{b}=\frac{40.5}{b}$ $b=\frac{40.5}{tan~8.4°}=274.27$
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