Algebra and Trigonometry 10th Edition

Published by Cengage Learning
ISBN 10: 9781337271172
ISBN 13: 978-1-33727-117-2

Chapter 6 - 6.7 - Applications and Models - 6.7 Exercises - Page 494: 14


$$ h=2.83$$

Work Step by Step

For an isosceles triangle, given the base angle, $\theta$, we know that the height is: $$h=.5btan\theta \\ h =.5(14)tan(22^{\circ})\\ h=2.83$$
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