Algebra and Trigonometry 10th Edition

Published by Cengage Learning
ISBN 10: 9781337271172
ISBN 13: 978-1-33727-117-2

Chapter 6 - 6.2 - Right Triangle Trigonometry - 6.2 Exercises - Page 444: 78


False. $(5°)^2=25 (°)^2$, that is $25~deg^2$. It is the measure of a solid angle (Do a search about solid angles). So it makes no sense to evaluate $tan(25~deg^2)$

Work Step by Step

But, assume that $tan[(5°)^2]=tan~25°$. We have that: $tan[(5°)^2]=tan~25°\approx0.466\ne(tan~5°)^2\approx0.00765$
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