Algebra and Trigonometry 10th Edition

Published by Cengage Learning
ISBN 10: 9781337271172
ISBN 13: 978-1-33727-117-2

Chapter 6 - 6.2 - Right Triangle Trigonometry - 6.2 Exercises - Page 444: 76


True. It is because $cos~60°=sin~30°$

Work Step by Step

$cos~60°-sin~30°=\frac{1}{2}-\frac{1}{2}=0$ Also, remember that $sin(90°-θ)=cos~θ$. So: $sin~30°=sin(90°-60°)=cos~60°$
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