Algebra and Trigonometry 10th Edition

Published by Cengage Learning
ISBN 10: 9781337271172
ISBN 13: 978-1-33727-117-2

Chapter 6 - 6.2 - Right Triangle Trigonometry - 6.2 Exercises - Page 441: 16

Answer

$cos~\theta=\frac{adj}{hyp}=\frac{4}{5}$ $tan~\theta=\frac{opp}{adj}=\frac{3}{4}$ $cot~\theta=\frac{adj}{opp}=\frac{4}{3}$ $sec~\theta=\frac{hyp}{adj}=\frac{5}{4}$ $csc~\theta=\frac{hyp}{opp}=\frac{5}{3}$

Work Step by Step

$sin~\theta=\frac{opp}{hyp}$ $\frac{3}{5}=\frac{opp}{hyp}$ Use the pythagorean theorem to find the adjacent side of $\theta$ $5^2=3^2+adj^2$ $adj^2=25-9=16$ $adj=4$ $cos~\theta=\frac{adj}{hyp}=\frac{4}{5}$ $tan~\theta=\frac{opp}{adj}=\frac{3}{4}$ $cot~\theta=\frac{adj}{opp}=\frac{4}{3}$ $sec~\theta=\frac{hyp}{adj}=\frac{5}{4}$ $csc~\theta=\frac{hyp}{opp}=\frac{5}{3}$
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