Answer
$sin~θ=\frac{5}{13}$
$cos~θ=\frac{12}{13}$
$tan~θ=\frac{5}{12}$
$csc~θ=\frac{13}{5}$
$sec~θ=\frac{13}{12}$
$cot~θ=\frac{12}{5}$
Work Step by Step
First, let's evaluate the side adjacent to $θ$:
$(hyp)^2=(opp)^2+(adj)^2$
$13^2=5^2+(adj)^2$
$169-25=(adj)^2$
$144=(adj)^2$
$adj=12$
$sin~θ=\frac{opp}{hyp}=\frac{5}{13}$
$cos~θ=\frac{adj}{hyp}=\frac{12}{13}$
$tan~θ=\frac{opp}{adj}=\frac{5}{12}$
$csc~θ=\frac{hyp}{opp}=\frac{13}{5}$
$sec~θ=\frac{hyp}{adj}=\frac{13}{12}$
$cot~θ=\frac{adj}{opp}=\frac{12}{5}$