Algebra and Trigonometry 10th Edition

Published by Cengage Learning
ISBN 10: 9781337271172
ISBN 13: 978-1-33727-117-2

Chapter 5 - Review Exercises - Page 414: 93


$x=3.729$ or $x=-0.729$

Work Step by Step

$\ln x+\ln(x-3)=1$ $\ln x(x-3)=1$ $\ln(x^2-3x)=1$ $x^2-3x=e$ $x^2-3x-e=0~~$ ($a=1,b=-3,c=-e$): $x=\frac{-b±\sqrt {b^2-4ac}}{2a}=\frac{3±\sqrt {(-3)^2-4(1)(-e)}}{2(1)}=\frac{3±\sqrt {9+4e}}{2}$ $x=3.729$ or $x=-0.729$
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