Answer
The function $y=\frac{6}{1+2e^{-2x}}$ matches with the graph labeled (c).
Work Step by Step
y-axis intercept ($x=0)$:
$y=\frac{6}{1+2e^{-2(0)}}=\frac{6}{1+2e^0}=\frac{6}{3}=2$
$e^{-2x}\rightarrow0$ as $x\rightarrow+\infty$
So, $y\rightarrow\frac{6}{1+0}=6$ as $x\rightarrow+\infty$
