Algebra and Trigonometry 10th Edition

Published by Cengage Learning
ISBN 10: 9781337271172
ISBN 13: 978-1-33727-117-2

Chapter 5 - Cumulative Test for Chapters 3-5 - Page 417: 40c

Answer

$t\approx9~years$

Work Step by Step

Make $p=800$: $800=\frac{1200}{1+3e^{-\frac{t}{5}}}$ $1+3e^{-\frac{t}{5}}=\frac{1200}{800}=1.5$ $3e^{-\frac{t}{5}}=1.5-1=0.5$ $e^{-\frac{t}{5}}=\frac{0.5}{3}$ $\ln e^{-\frac{t}{5}}=\ln\frac{0.5}{3}$ $-\frac{t}{5}=\ln\frac{0.5}{3}=\ln0.5-\ln3$ $t=5(\ln3-\ln0.5)$ $t=8.959\approx9~years$
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