Answer
$\ln(x+5)+\ln(x-5)-4\ln x$, where $x\gt5$
Work Step by Step
$\ln(\frac{x^2-25}{x^4})=\ln(\frac{x^2-5^2}{x^4})=\ln[\frac{(x+5)(x-5)}{x^4}]=\ln(x+5)+\ln(x-5)-\ln x^4=\ln(x+5)+\ln(x-5)-4\ln x$
Algebra and Trigonometry 10th Edition
by Larson, Ron
Published by
Cengage Learning
ISBN 10:
9781337271172
ISBN 13:
978-1-33727-117-2
Chapter 5 - Cumulative Test for Chapters 3-5 - Page 417: 29
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