## Algebra and Trigonometry 10th Edition

$\ln(x+5)+\ln(x-5)-4\ln x$, where $x\gt5$
$\ln(\frac{x^2-25}{x^4})=\ln(\frac{x^2-5^2}{x^4})=\ln[\frac{(x+5)(x-5)}{x^4}]=\ln(x+5)+\ln(x-5)-\ln x^4=\ln(x+5)+\ln(x-5)-4\ln x$