Algebra and Trigonometry 10th Edition

Published by Cengage Learning
ISBN 10: 9781337271172
ISBN 13: 978-1-33727-117-2

Chapter 5 - Cumulative Test for Chapters 3-5 - Page 416: 1



Work Step by Step

$f(x)=a(x-k)^2+h~~$ (Standard form, where $(k,h)$ is the vertex) $f(x)=a[x-(-8)]^2+5$ $f(x)=a(x+8)^2+5$ Use the point $(-4,-7)$ to find $a$: $-7=a(-4+8)^2+5$ $-7-5=a(4)^2$ $-12=16a$ $a=\frac{-12}{16}=-\frac{3}{4}$ $f(x)=-\frac{3}{4}(x+8)^2+5$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.