Answer
$\log_a(x+y)=(\log_ax)(\log_ay)$
False.
Work Step by Step
$\log_a(x+y)\ne(\log_ax)(\log_ay)$
$a^{\log_a(x+y)}\ne a^{(\log_ax)(\log_ay)}$
$x+y\ne (a^{\log_ax})^{\log_ay}$
$x+y\ne x^{\log_ay}$
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