Algebra and Trigonometry 10th Edition

Published by Cengage Learning
ISBN 10: 9781337271172
ISBN 13: 978-1-33727-117-2

Chapter 5 - 5.1 - Exponential Functions and Their Graphs - 5.1 Exercises - Page 369: 62b


2003: $58.48~million$ 2015: $62.17~million$

Work Step by Step

$P(t)=57.59e^{0.0051t}$ 2003 corresponds to $t=3$: $P(3)=57.59e^{0.0051\times3}=57.59e^{0.0153}=58.48$ 2015 corresponds to $t=15$: $P(15)=57.59e^{0.0051\times15}=57.59e^{0.0765}=62.17$
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