Answer
$x_1=3$ and $x_2=2$
Work Step by Step
$e^{x^2+6}=e^{5x}$
Applying the One-to-One Property:
$x^2+6=5x$
$x^2-5x+6=0$ ($a=1,~b=-5,~c=6$)
$x=\frac{-(-5)±\sqrt {(-5)^2-4(1)(6)}}{2(1)}$
$x=\frac{5±\sqrt {1}}{2}=\frac{5±1}{2}$
$x_1=\frac{6}{2}=3$ and $x_2=\frac{4}{2}=2$
