Algebra and Trigonometry 10th Edition

Published by Cengage Learning
ISBN 10: 9781337271172
ISBN 13: 978-1-33727-117-2

Chapter 4 - 4.3 - Conics - 4.3 Exercises - Page 337: 22

Answer

$x^2=2y$

Work Step by Step

Focus is on the y-axis. $(0,p)=(0,\frac{1}{2})$ $p=\frac{1}{2}$ Parabola in the standard form with the vertex at origin (vertical axis): $x^2=4py$ $x^2=4(\frac{1}{2})y$ $x^2=2y$
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